02.45tangraph

Graphs of the Tangent Function

Recall, for all trig graphs,

  • the median line is a horizontal line through the centre of the graph
  • the amplitude is the maximum height above the median line
  • the period is the distance in the x-direction to complete one cycle

Graph of y = tan(x)

02.45tan1.gif

For the graph $y = \tan(x)$

  • Median line: $y = 0$
  • Amplitude: (no amplitude)
  • Period = $\pi$
  • Asymptotes: $x=(2k+1)\dfrac{\pi}{2}, \; k\in Z$
  • Domain: $x \in R\backslash \left\{ (2k+1)\dfrac{\pi}{2}, \; k\in Z \right\}$
  • Extra point: $\left( \dfrac{\pi}{4} , \; 1 \right)$
  • Range: $y \in R$
  • x-intercepts: $x = k\pi, \; k \in Z$

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Dilations: y = atan(nx)

02.45period.gif

$y = a\tan(nx)$ causes:

  • a dilation by a factor of a in the y-direction
  • a dilation by a factor of $\frac{1}{n}$ in the x-direction
  • Asymptotes: $x=(2k+1)\dfrac{\pi}{2n}, \; k\in Z$
  • Domain: $x \in R\backslash \left\{ (2k+1)\dfrac{\pi}{2n}, \; k\in Z \right\}$
  • extra point: $\left( \dfrac{\pi}{4n} , \; a \right)$

Recall that if a is negative, we get a reflection across the x-axis (in the y-direction)

And, if n is negative, we get a reflection across the y-axis (in the x-direction)

Example 1

Sketch the graph of $y = 2\tan \big(\frac{x}{2} \big)$

Solution

02.45tan2.gif

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  • Median line: $y = 0$
  • Period = $\dfrac{\pi}{1/2}=2\pi$
  • Asymptotes: $x = (2k + 1)\pi, \; k \in Z$
  • Domain: $x \in R\backslash \left\{ (2k + 1)\pi, \; k \in Z \right\}$
  • Range: $y \in R$
  • x-intercepts: $x = 2k\pi,\; k \in Z$ {found by solving $y = 0$}

Translations: y = tan(x – b) + c

$y = tan(x - b) + c$ causes

  • a translation by b units to the right
  • a translation by c units up

Example 2

Sketch $y = \tan \left( x + \dfrac{\pi}{6} \right) -1$

Solution

02.45tan3.gif
  • Median line: $y = -1$
  • Period = $\pi$
  • Asymptotes: $x=k\pi+\dfrac{\pi}{3},\; k\in Z$
  • Domain: $x \in R \backslash \left\{ k\pi+\dfrac{\pi}{3},\; k\in Z \right\}$
  • Range: $y \in R$

The points on the median line can be found by solving y = –1

  • Median points: $x=k\pi-\dfrac{\pi}{6},\; k \in Z$

x-intercepts can be found by solving y = 0

  • x-intecepts: $x=k\pi+\dfrac{\pi}{12},\; k \in Z$

Summary

$y = a \tan \big(n(x-b) \big)+c$

  • Median line: $y = c$
  • Dilated by a factor of a from the x-axis (in the y-direction)
  • Dilated by a factor of 1/n from the y-axis (in the x-direction)
  • Period = $\frac{\pi}{n}$
  • Translated b units to the right
  • Translated c units up
  • To find median points: solve $y = c$
  • To find x-intercepts: solve $y = 0$
  • Asymptotes: $x=(2k+1) \left(\dfrac{\pi}{2n} + b \right), \; k\in Z$
  • Domain: $x \in R\backslash \left\{ (2k+1)\left( \dfrac{\pi}{2n} +b \right), \; k\in Z \right\}$
  • extra point: $\left( \dfrac{\pi}{4n} + b , \; a + c \right)$

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